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13311002111 = 111210091101
BaseRepresentation
bin11000110010110010…
…11100010111111111
31021100122222222011012
430121121130113333
5204230104031421
610040500545435
7650600436221
oct143131342777
937318888135
1013311002111
1157107939a0
1226b59b227b
131341952514
14903ba4411
1552d8d595b
hex31965c5ff

13311002111 has 4 divisors (see below), whose sum is σ = 14521093224. Its totient is φ = 12100911000.

The previous prime is 13311002101. The next prime is 13311002137. The reversal of 13311002111 is 11120011331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13311002111 - 210 = 13311001087 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311002101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605045540 + ... + 605045561.

It is an arithmetic number, because the mean of its divisors is an integer number (3630273306).

Almost surely, 213311002111 is an apocalyptic number.

13311002111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13311002111 is a deficient number, since it is larger than the sum of its proper divisors (1210091113).

13311002111 is a wasteful number, since it uses less digits than its factorization.

13311002111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1210091112.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 13311002111 its reverse (11120011331), we get a palindrome (24431013442).

The spelling of 13311002111 in words is "thirteen billion, three hundred eleven million, two thousand, one hundred eleven".

Divisors: 1 11 1210091101 13311002111