13311010441231 has 4 divisors (see below), whose sum is σ = 13311947388672. Its totient is φ = 13310073493792.

The previous prime is 13311010441171. The next prime is 13311010441273. The reversal of 13311010441231 is 13214401011331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13311010441231 - 2¹⁷ = 13311010310159 is a prime.

It is a super-2 number, since 2×13311010441231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13311010441196 and 13311010441205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311010441031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468452410 + ... + 468480823.

It is an arithmetic number, because the mean of its divisors is an integer number (3327986847168).

Almost surely, 2^{13311010441231} is an apocalyptic number.

13311010441231 is a deficient number, since it is larger than the sum of its proper divisors (936947441).

13311010441231 is an equidigital number, since it uses as much as digits as its factorization.

13311010441231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 936947440.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 13311010441231 its reverse (13214401011331), we get a palindrome (26525411452562).

The spelling of 13311010441231 in words is "thirteen trillion, three hundred eleven billion, ten million, four hundred forty-one thousand, two hundred thirty-one".