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133110143142014 = 266555071571007
BaseRepresentation
bin11110010001000000011110…
…110011000100100001111110
3122110022012112202000220112002
4132101000132303010201332
5114421334033121021024
61151033542223142302
740015614302213633
oct3621003663044176
9573265482026462
10133110143142014
113945a7706a17a5
1212b19779744992
13593730414c4ac
1424c27cb29a18a
15105c77875c6ae
hex79101ecc487e

133110143142014 has 4 divisors (see below), whose sum is σ = 199665214713024. Its totient is φ = 66555071571006.

The previous prime is 133110143142007. The next prime is 133110143142017. The reversal of 133110143142014 is 410241341011331.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×1331101431420143 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133110143142017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33277535785502 + ... + 33277535785505.

It is an arithmetic number, because the mean of its divisors is an integer number (49916303678256).

Almost surely, 2133110143142014 is an apocalyptic number.

133110143142014 is a deficient number, since it is larger than the sum of its proper divisors (66555071571010).

133110143142014 is an equidigital number, since it uses as much as digits as its factorization.

133110143142014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66555071571009.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 133110143142014 its reverse (410241341011331), we get a palindrome (543351484153345).

The spelling of 133110143142014 in words is "one hundred thirty-three trillion, one hundred ten billion, one hundred forty-three million, one hundred forty-two thousand, fourteen".

Divisors: 1 2 66555071571007 133110143142014