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13311022332134 = 26655511166067
BaseRepresentation
bin1100000110110011011011…
…0000011111100011100110
31202010112002000220001012002
43001230312300133203212
53221041433204112014
644150555500325302
72542455353661122
oct301546660374346
952115060801162
1013311022332134
11427219a0a829a
1215ab922543832
137572bb230437
14340384dac582
151813b4846dde
hexc1b36c1f8e6

13311022332134 has 4 divisors (see below), whose sum is σ = 19966533498204. Its totient is φ = 6655511166066.

The previous prime is 13311022332119. The next prime is 13311022332143. The reversal of 13311022332134 is 43123322011331.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13311022332097 and 13311022332106.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3327755583032 + ... + 3327755583035.

It is an arithmetic number, because the mean of its divisors is an integer number (4991633374551).

Almost surely, 213311022332134 is an apocalyptic number.

13311022332134 is a deficient number, since it is larger than the sum of its proper divisors (6655511166070).

13311022332134 is an equidigital number, since it uses as much as digits as its factorization.

13311022332134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6655511166069.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 13311022332134 its reverse (43123322011331), we get a palindrome (56434344343465).

The spelling of 13311022332134 in words is "thirteen trillion, three hundred eleven billion, twenty-two million, three hundred thirty-two thousand, one hundred thirty-four".

Divisors: 1 2 6655511166067 13311022332134