Base | Representation |
---|---|
bin | 111101111110111111… |
… | …1010001101101100011 |
3 | 110201120200101220202102 |
4 | 1323331333101231203 |
5 | 4140102210222042 |
6 | 141052222241015 |
7 | 12421411250501 |
oct | 1737577215543 |
9 | 421520356672 |
10 | 133110242147 |
11 | 514a7297093 |
12 | 2196a42616b |
13 | c7243776bc |
14 | 662a5ab671 |
15 | 36e0e31b32 |
hex | 1efdfd1b63 |
133110242147 has 2 divisors, whose sum is σ = 133110242148. Its totient is φ = 133110242146.
The previous prime is 133110242119. The next prime is 133110242171. The reversal of 133110242147 is 741242011331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133110242147 is a prime.
It is not a weakly prime, because it can be changed into another prime (133110242197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66555121073 + 66555121074.
It is an arithmetic number, because the mean of its divisors is an integer number (66555121074).
Almost surely, 2133110242147 is an apocalyptic number.
133110242147 is a deficient number, since it is larger than the sum of its proper divisors (1).
133110242147 is an equidigital number, since it uses as much as digits as its factorization.
133110242147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 133110242147 its reverse (741242011331), we get a palindrome (874352253478).
The spelling of 133110242147 in words is "one hundred thirty-three billion, one hundred ten million, two hundred forty-two thousand, one hundred forty-seven".
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