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13311032089 is a prime number
BaseRepresentation
bin11000110010110011…
…00011101100011001
31021100200001111021111
430121121203230121
5204230111011324
610040501340321
7650600622505
oct143131435431
937320044244
1013311032089
115710804473
1226b5a076a1
131341963064
14903bb1305
1552d8de794
hex319663b19

13311032089 has 2 divisors, whose sum is σ = 13311032090. Its totient is φ = 13311032088.

The previous prime is 13311032017. The next prime is 13311032129. The reversal of 13311032089 is 98023011331.

13311032089 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11477479689 + 1833552400 = 107133^2 + 42820^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311032089 - 211 = 13311030041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13311032089.

It is not a weakly prime, because it can be changed into another prime (13311032789) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655516044 + 6655516045.

It is an arithmetic number, because the mean of its divisors is an integer number (6655516045).

Almost surely, 213311032089 is an apocalyptic number.

It is an amenable number.

13311032089 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311032089 is an equidigital number, since it uses as much as digits as its factorization.

13311032089 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 13311032089 in words is "thirteen billion, three hundred eleven million, thirty-two thousand, eighty-nine".