1331110099129 has 2 divisors, whose sum is σ = 1331110099130. Its totient is φ = 1331110099128.

The previous prime is 1331110099097. The next prime is 1331110099147. The reversal of 1331110099129 is 9219900111331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1199576943504 + 131533155625 = 1095252^2 + 362675^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331110099129 - 2⁵ = 1331110099097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1331110099091 and 1331110099100.

It is not a weakly prime, because it can be changed into another prime (1331110094129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665555049564 + 665555049565.

It is an arithmetic number, because the mean of its divisors is an integer number (665555049565).

Almost surely, 2^{1331110099129} is an apocalyptic number.

It is an amenable number.

1331110099129 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331110099129 is an equidigital number, since it uses as much as digits as its factorization.

1331110099129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13122, while the sum is 40.

The spelling of 1331110099129 in words is "one trillion, three hundred thirty-one billion, one hundred ten million, ninety-nine thousand, one hundred twenty-nine".