13311101320 has 256 divisors, whose sum is σ = 36663840000. Its totient is φ = 4286545920.

The previous prime is 13311101317. The next prime is 13311101327. The reversal of 13311101320 is 2310111331.

It is a junction number, because it is equal to n+sod(n) for n = 13311101294 and 13311101303.

It is not an unprimeable number, because it can be changed into a prime (13311101327) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 32545276 + ... + 32545684.

It is an arithmetic number, because the mean of its divisors is an integer number (143218125).

Almost surely, 2^13311101320 is an apocalyptic number.

13311101320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311101320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18331920000).

13311101320 is an abundant number, since it is smaller than the sum of its proper divisors (23352738680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311101320 is a wasteful number, since it uses less digits than its factorization.

13311101320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 696 (or 692 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13311101320 its reverse (2310111331), we get a palindrome (15621212651).

The spelling of 13311101320 in words is "thirteen billion, three hundred eleven million, one hundred one thousand, three hundred twenty".