Base | Representation |
---|---|
bin | 10011010111101100010… |
… | …110100001100100101001 |
3 | 11201020211100201111001002 |
4 | 103113230112201210221 |
5 | 133302103204101441 |
6 | 2455300435404345 |
7 | 165112103126411 |
oct | 23275426414451 |
9 | 4636740644032 |
10 | 1331110222121 |
11 | 473580022569 |
12 | 195b8a1536b5 |
13 | 986a54abbb4 |
14 | 485d7233641 |
15 | 2495a253b9b |
hex | 135ec5a1929 |
1331110222121 has 2 divisors, whose sum is σ = 1331110222122. Its totient is φ = 1331110222120.
The previous prime is 1331110222093. The next prime is 1331110222129. The reversal of 1331110222121 is 1212220111331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1051865616025 + 279244606096 = 1025605^2 + 528436^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331110222121 - 222 = 1331106027817 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1331110222093 and 1331110222102.
It is not a weakly prime, because it can be changed into another prime (1331110222129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665555111060 + 665555111061.
It is an arithmetic number, because the mean of its divisors is an integer number (665555111061).
Almost surely, 21331110222121 is an apocalyptic number.
It is an amenable number.
1331110222121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331110222121 is an equidigital number, since it uses as much as digits as its factorization.
1331110222121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1331110222121 its reverse (1212220111331), we get a palindrome (2543330333452).
The spelling of 1331110222121 in words is "one trillion, three hundred thirty-one billion, one hundred ten million, two hundred twenty-two thousand, one hundred twenty-one".
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