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1331110311140 = 22566555515557
BaseRepresentation
bin10011010111101100010…
…110110111010011100100
311201020211100220000011002
4103113230112313103210
5133302103214424030
62455300441332432
7165112103650061
oct23275426672344
94636740800132
101331110311140
11473580083435
12195b8a197118
13986a551057c
14485d7257c68
152495a270245
hex135ec5b74e4

1331110311140 has 12 divisors (see below), whose sum is σ = 2795331653436. Its totient is φ = 532444124448.

The previous prime is 1331110311053. The next prime is 1331110311143. The reversal of 1331110311140 is 411130111331.

It can be written as a sum of positive squares in 2 ways, for example, as 804928363684 + 526181947456 = 897178^2 + 725384^2 .

It is a Harshad number since it is a multiple of its sum of digits (20), and also a Moran number because the ratio is a prime number: 66555515557 = 1331110311140 / (1 + 3 + 3 + 1 + 1 + 1 + 0 + 3 + 1 + 1 + 1 + 4 + 0).

It is not an unprimeable number, because it can be changed into a prime (1331110311143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33277757759 + ... + 33277757798.

It is an arithmetic number, because the mean of its divisors is an integer number (232944304453).

Almost surely, 21331110311140 is an apocalyptic number.

1331110311140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1331110311140 is an abundant number, since it is smaller than the sum of its proper divisors (1464221342296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1331110311140 is a wasteful number, since it uses less digits than its factorization.

1331110311140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66555515566 (or 66555515564 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1331110311140 its reverse (411130111331), we get a palindrome (1742240422471).

The spelling of 1331110311140 in words is "one trillion, three hundred thirty-one billion, one hundred ten million, three hundred eleven thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 66555515557 133111031114 266222062228 332777577785 665555155570 1331110311140