13311134304040 has 16 divisors (see below), whose sum is σ = 29950052184180. Its totient is φ = 5324453721600.

The previous prime is 13311134303977. The next prime is 13311134304047. The reversal of 13311134304040 is 4040343111331.

13311134304040 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 12354114284964 + 957020019076 = 3514842^2 + 978274^2 .

It is not an unprimeable number, because it can be changed into a prime (13311134304047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166389178761 + ... + 166389178840.

Almost surely, 2^{13311134304040} is an apocalyptic number.

13311134304040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13311134304040 is an abundant number, since it is smaller than the sum of its proper divisors (16638917880140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311134304040 is a wasteful number, since it uses less digits than its factorization.

13311134304040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 332778357612 (or 332778357608 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13311134304040 its reverse (4040343111331), we get a palindrome (17351477415371).

The spelling of 13311134304040 in words is "thirteen trillion, three hundred eleven billion, one hundred thirty-four million, three hundred four thousand, forty".