Base | Representation |
---|---|
bin | 10011010111101100100… |
… | …101010111000101000110 |
3 | 11201020211122001001222211 |
4 | 103113230211113011012 |
5 | 133302110203030202 |
6 | 2455301055014034 |
7 | 165112151155213 |
oct | 23275445270506 |
9 | 4636748031884 |
10 | 1331114111302 |
11 | 473582239568 |
12 | 195b8b50a31a |
13 | 986a62411a1 |
14 | 485d7966b0a |
15 | 2495a7711d7 |
hex | 135ec957146 |
1331114111302 has 4 divisors (see below), whose sum is σ = 1996671166956. Its totient is φ = 665557055650.
The previous prime is 1331114111297. The next prime is 1331114111321. The reversal of 1331114111302 is 2031114111331.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332778527824 + ... + 332778527827.
It is an arithmetic number, because the mean of its divisors is an integer number (499167791739).
Almost surely, 21331114111302 is an apocalyptic number.
1331114111302 is a deficient number, since it is larger than the sum of its proper divisors (665557055654).
1331114111302 is an equidigital number, since it uses as much as digits as its factorization.
1331114111302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 665557055653.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 1331114111302 its reverse (2031114111331), we get a palindrome (3362228222633).
The spelling of 1331114111302 in words is "one trillion, three hundred thirty-one billion, one hundred fourteen million, one hundred eleven thousand, three hundred two".
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