Base | Representation |
---|---|
bin | 1100000110110100000110… |
… | …0101100101101011101111 |
3 | 1202010112112200202220020021 |
4 | 3001231001211211223233 |
5 | 3221042321212214043 |
6 | 44151025510503011 |
7 | 2542463021221144 |
oct | 301550145455357 |
9 | 52115480686207 |
10 | 13311204023023 |
11 | 4272282715355 |
12 | 15ab973364a67 |
13 | 757319a76b3a |
14 | 3403a11863cb |
15 | 1813c57863ed |
hex | c1b41965aef |
13311204023023 has 16 divisors (see below), whose sum is σ = 13922374348800. Its totient is φ = 12702741635584.
The previous prime is 13311204023017. The next prime is 13311204023027. The reversal of 13311204023023 is 32032040211331.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13311204023023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13311204023027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 104269890 + ... + 104397472.
It is an arithmetic number, because the mean of its divisors is an integer number (870148396800).
Almost surely, 213311204023023 is an apocalyptic number.
13311204023023 is a deficient number, since it is larger than the sum of its proper divisors (611170325777).
13311204023023 is a wasteful number, since it uses less digits than its factorization.
13311204023023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 138158.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13311204023023 its reverse (32032040211331), we get a palindrome (45343244234354).
The spelling of 13311204023023 in words is "thirteen trillion, three hundred eleven billion, two hundred four million, twenty-three thousand, twenty-three".
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