13311210413440 has 192 divisors, whose sum is σ = 33595319164320. Its totient is φ = 5042715033600.

The previous prime is 13311210413419. The next prime is 13311210413513. The reversal of 13311210413440 is 4431401211331.

13311210413440 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×13311210413440³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13311210413399 and 13311210413408.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1014490080 + ... + 1014503200.

Almost surely, 2^{13311210413440} is an apocalyptic number.

13311210413440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311210413440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16797659582160).

13311210413440 is an abundant number, since it is smaller than the sum of its proper divisors (20284108750880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311210413440 is a wasteful number, since it uses less digits than its factorization.

13311210413440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17569 (or 17538 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 13311210413440 its reverse (4431401211331), we get a palindrome (17742611624771).

The spelling of 13311210413440 in words is "thirteen trillion, three hundred eleven billion, two hundred ten million, four hundred thirteen thousand, four hundred forty".