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13311210414331 is a prime number
BaseRepresentation
bin1100000110110100000111…
…1101111110000011111011
31202010112120010210121110101
43001231001331332003323
53221042324331224311
644151030255500231
72542463126440534
oct301550175760373
952115503717411
1013311210414331
114272286290225
1215ab975527677
1375731b1a3c8b
143403a1d6b68b
151813c60e9ec1
hexc1b41f7e0fb

13311210414331 has 2 divisors, whose sum is σ = 13311210414332. Its totient is φ = 13311210414330.

The previous prime is 13311210414269. The next prime is 13311210414377. The reversal of 13311210414331 is 13341401211331.

It is a strong prime.

It is an emirp because it is prime and its reverse (13341401211331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13311210414331 - 225 = 13311176859899 is a prime.

It is a super-2 number, since 2×133112104143312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13311210414331.

It is not a weakly prime, because it can be changed into another prime (13311210414391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655605207165 + 6655605207166.

It is an arithmetic number, because the mean of its divisors is an integer number (6655605207166).

Almost surely, 213311210414331 is an apocalyptic number.

13311210414331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311210414331 is an equidigital number, since it uses as much as digits as its factorization.

13311210414331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 13311210414331 its reverse (13341401211331), we get a palindrome (26652611625662).

The spelling of 13311210414331 in words is "thirteen trillion, three hundred eleven billion, two hundred ten million, four hundred fourteen thousand, three hundred thirty-one".