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13311211210041 = 312233628021589
BaseRepresentation
bin1100000110110100001000…
…0001000000010100111001
31202010112120012022000222010
43001231002001000110321
53221042330032210131
644151030324520133
72542463136263433
oct301550201002471
952115505260863
1013311211210041
114272286784038
1215ab975850049
1375731b3c2204
143403a20d7653
151813c6205b46
hexc1b42040539

13311211210041 has 8 divisors (see below), whose sum is σ = 17762793704640. Its totient is φ = 8866884761072.

The previous prime is 13311211210013. The next prime is 13311211210043. The reversal of 13311211210041 is 14001211211331.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13311211210041 - 217 = 13311211078969 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13311211210043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1814007126 + ... + 1814014463.

It is an arithmetic number, because the mean of its divisors is an integer number (2220349213080).

Almost surely, 213311211210041 is an apocalyptic number.

It is an amenable number.

13311211210041 is a deficient number, since it is larger than the sum of its proper divisors (4451582494599).

13311211210041 is a wasteful number, since it uses less digits than its factorization.

13311211210041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3628022815.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 13311211210041 its reverse (14001211211331), we get a palindrome (27312422421372).

The spelling of 13311211210041 in words is "thirteen trillion, three hundred eleven billion, two hundred eleven million, two hundred ten thousand, forty-one".

Divisors: 1 3 1223 3669 3628021589 10884064767 4437070403347 13311211210041