13311211210042 has 4 divisors (see below), whose sum is σ = 19966816815066. Its totient is φ = 6655605605020.

The previous prime is 13311211210013. The next prime is 13311211210043. The reversal of 13311211210042 is 24001211211331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12607761649081 + 703449560961 = 3550741^2 + 838719^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13311211209995 and 13311211210022.

It is not an unprimeable number, because it can be changed into a prime (13311211210043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3327802802509 + ... + 3327802802512.

Almost surely, 2^{13311211210042} is an apocalyptic number.

13311211210042 is a deficient number, since it is larger than the sum of its proper divisors (6655605605024).

13311211210042 is an equidigital number, since it uses as much as digits as its factorization.

13311211210042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6655605605023.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 13311211210042 its reverse (24001211211331), we get a palindrome (37312422421373).

The spelling of 13311211210042 in words is "thirteen trillion, three hundred eleven billion, two hundred eleven million, two hundred ten thousand, forty-two".