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133112300002110 = 23251121343151179809
BaseRepresentation
bin11110010001000010011111…
…010110110101101100111110
3122110022102010001112202100100
4132101002133112311230332
5114421402442300031420
61151034540232141530
740016021612216532
oct3621023726655476
9573272101482310
10133112300002110
1139460678136700
1212b1a07bb378a6
135937588c58080
1424c2953907bc2
15105c852ca7190
hex79109f5b5b3e

133112300002110 has 1152 divisors, whose sum is σ = 424863402163200. Its totient is φ = 28704969216000.

The previous prime is 133112300002109. The next prime is 133112300002133. The reversal of 133112300002110 is 11200003211331.

133112300002110 is a `hidden beast` number, since 1 + 331 + 1 + 2 + 300 + 0 + 0 + 21 + 10 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 575 ways as a sum of consecutive naturals, for example, 164539307386 + ... + 164539308194.

It is an arithmetic number, because the mean of its divisors is an integer number (368805036600).

Almost surely, 2133112300002110 is an apocalyptic number.

133112300002110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 133112300002110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (212431701081600).

133112300002110 is an abundant number, since it is smaller than the sum of its proper divisors (291751102161090).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133112300002110 is a wasteful number, since it uses less digits than its factorization.

133112300002110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1230 (or 1216 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 133112300002110 its reverse (11200003211331), we get a palindrome (144312303213441).

The spelling of 133112300002110 in words is "one hundred thirty-three trillion, one hundred twelve billion, three hundred million, two thousand, one hundred ten".