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13311230000617 is a prime number
BaseRepresentation
bin1100000110110100001100…
…1000101011110111101001
31202010112121111122200210101
43001231003020223313221
53221042344340004432
644151032235345401
72542463455064443
oct301550310536751
952115544580711
1013311230000617
11427229634873a
1215ab97bbb2261
13757322270cb3
143403a47c9493
151813c7bb84e7
hexc1b4322bde9

13311230000617 has 2 divisors, whose sum is σ = 13311230000618. Its totient is φ = 13311230000616.

The previous prime is 13311230000611. The next prime is 13311230000639. The reversal of 13311230000617 is 71600003211331.

13311230000617 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12967950018816 + 343279981801 = 3601104^2 + 585901^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311230000617 - 27 = 13311230000489 is a prime.

It is not a weakly prime, because it can be changed into another prime (13311230000611) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655615000308 + 6655615000309.

It is an arithmetic number, because the mean of its divisors is an integer number (6655615000309).

Almost surely, 213311230000617 is an apocalyptic number.

It is an amenable number.

13311230000617 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311230000617 is an equidigital number, since it uses as much as digits as its factorization.

13311230000617 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2268, while the sum is 28.

Adding to 13311230000617 its reverse (71600003211331), we get a palindrome (84911233211948).

The spelling of 13311230000617 in words is "thirteen trillion, three hundred eleven billion, two hundred thirty million, six hundred seventeen", and thus it is an aban number.