Base | Representation |
---|---|
bin | 11000110010110100… |
… | …10100110010000001 |
3 | 1021100200102201002022 |
4 | 30121122110302001 |
5 | 204230133430103 |
6 | 10040505531225 |
7 | 650602420631 |
oct | 143132246201 |
9 | 37320381068 |
10 | 13311233153 |
11 | 5710931539 |
12 | 26b5aa3b15 |
13 | 1341a0372a |
14 | 903c246c1 |
15 | 52d92e138 |
hex | 319694c81 |
13311233153 has 2 divisors, whose sum is σ = 13311233154. Its totient is φ = 13311233152.
The previous prime is 13311233101. The next prime is 13311233171. The reversal of 13311233153 is 35133211331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7321711489 + 5989521664 = 85567^2 + 77392^2 .
It is an emirp because it is prime and its reverse (35133211331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13311233153 - 214 = 13311216769 is a prime.
It is not a weakly prime, because it can be changed into another prime (13311236153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655616576 + 6655616577.
It is an arithmetic number, because the mean of its divisors is an integer number (6655616577).
Almost surely, 213311233153 is an apocalyptic number.
It is an amenable number.
13311233153 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311233153 is an equidigital number, since it uses as much as digits as its factorization.
13311233153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2430, while the sum is 26.
Adding to 13311233153 its reverse (35133211331), we get a palindrome (48444444484).
The spelling of 13311233153 in words is "thirteen billion, three hundred eleven million, two hundred thirty-three thousand, one hundred fifty-three".
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