Base | Representation |
---|---|
bin | 1100000110110100001101… |
… | …1001100111110000110010 |
3 | 1202010112121211000020210221 |
4 | 3001231003121213300302 |
5 | 3221042402004041432 |
6 | 44151032514443254 |
7 | 2542463540605114 |
oct | 301550331476062 |
9 | 52115554006727 |
10 | 13311234440242 |
11 | 4272298900252 |
12 | 15ab98159352a |
13 | 7573231669ab |
14 | 3403a52233b4 |
15 | 1813c8293b97 |
hex | c1b43667c32 |
13311234440242 has 4 divisors (see below), whose sum is σ = 19966851660366. Its totient is φ = 6655617220120.
The previous prime is 13311234440227. The next prime is 13311234440261. The reversal of 13311234440242 is 24204443211331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10214869837041 + 3096364603201 = 3196071^2 + 1759649^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13311234440198 and 13311234440207.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3327808610059 + ... + 3327808610062.
Almost surely, 213311234440242 is an apocalyptic number.
13311234440242 is a deficient number, since it is larger than the sum of its proper divisors (6655617220124).
13311234440242 is an equidigital number, since it uses as much as digits as its factorization.
13311234440242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6655617220123.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 13311234440242 its reverse (24204443211331), we get a palindrome (37515677651573).
The spelling of 13311234440242 in words is "thirteen trillion, three hundred eleven billion, two hundred thirty-four million, four hundred forty thousand, two hundred forty-two".
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