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13311234440242 = 26655617220121
BaseRepresentation
bin1100000110110100001101…
…1001100111110000110010
31202010112121211000020210221
43001231003121213300302
53221042402004041432
644151032514443254
72542463540605114
oct301550331476062
952115554006727
1013311234440242
114272298900252
1215ab98159352a
137573231669ab
143403a52233b4
151813c8293b97
hexc1b43667c32

13311234440242 has 4 divisors (see below), whose sum is σ = 19966851660366. Its totient is φ = 6655617220120.

The previous prime is 13311234440227. The next prime is 13311234440261. The reversal of 13311234440242 is 24204443211331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10214869837041 + 3096364603201 = 3196071^2 + 1759649^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13311234440198 and 13311234440207.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3327808610059 + ... + 3327808610062.

Almost surely, 213311234440242 is an apocalyptic number.

13311234440242 is a deficient number, since it is larger than the sum of its proper divisors (6655617220124).

13311234440242 is an equidigital number, since it uses as much as digits as its factorization.

13311234440242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6655617220123.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 13311234440242 its reverse (24204443211331), we get a palindrome (37515677651573).

The spelling of 13311234440242 in words is "thirteen trillion, three hundred eleven billion, two hundred thirty-four million, four hundred forty thousand, two hundred forty-two".

Divisors: 1 2 6655617220121 13311234440242