Base | Representation |
---|---|
bin | 1100000110110100011101… |
… | …0111100100001011001011 |
3 | 1202010112210110021100112002 |
4 | 3001231013113210023023 |
5 | 3221043021024310443 |
6 | 44151043253341215 |
7 | 2542465306464314 |
oct | 301550727441313 |
9 | 52115713240462 |
10 | 13311301010123 |
11 | 4272322439186 |
12 | 15ab99b93780b |
13 | 757333ba415c |
14 | 3403addd160b |
15 | 1813ce0432b8 |
hex | c1b475e42cb |
13311301010123 has 2 divisors, whose sum is σ = 13311301010124. Its totient is φ = 13311301010122.
The previous prime is 13311301010089. The next prime is 13311301010173. The reversal of 13311301010123 is 32101010311331.
13311301010123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13311301010123 - 216 = 13311300944587 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13311301010095 and 13311301010104.
It is not a weakly prime, because it can be changed into another prime (13311301010173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655650505061 + 6655650505062.
It is an arithmetic number, because the mean of its divisors is an integer number (6655650505062).
Almost surely, 213311301010123 is an apocalyptic number.
13311301010123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311301010123 is an equidigital number, since it uses as much as digits as its factorization.
13311301010123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 13311301010123 its reverse (32101010311331), we get a palindrome (45412311321454).
The spelling of 13311301010123 in words is "thirteen trillion, three hundred eleven billion, three hundred one million, ten thousand, one hundred twenty-three".
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