Base | Representation |
---|---|
bin | 111101111111000100… |
… | …1110111111001110110 |
3 | 110201120212122001021200 |
4 | 1323332021313321312 |
5 | 4140103413120042 |
6 | 141052401553330 |
7 | 12421444000323 |
oct | 1737611677166 |
9 | 421525561250 |
10 | 133113020022 |
11 | 514a8914154 |
12 | 2196b345846 |
13 | c724b0ac08 |
14 | 662aad1b4a |
15 | 36e12cec4c |
hex | 1efe277e76 |
133113020022 has 12 divisors (see below), whose sum is σ = 288411543420. Its totient is φ = 44371006668.
The previous prime is 133113020021. The next prime is 133113020041. The reversal of 133113020022 is 220020311331.
133113020022 is a `hidden beast` number, since 1 + 331 + 130 + 200 + 2 + 2 = 666.
133113020022 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (18), and also a Moran number because the ratio is a prime number: 7395167779 = 133113020022 / (1 + 3 + 3 + 1 + 1 + 3 + 0 + 2 + 0 + 0 + 2 + 2).
It is a junction number, because it is equal to n+sod(n) for n = 133113019977 and 133113020004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133113020021) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3697583872 + ... + 3697583907.
It is an arithmetic number, because the mean of its divisors is an integer number (24034295285).
Almost surely, 2133113020022 is an apocalyptic number.
133113020022 is an abundant number, since it is smaller than the sum of its proper divisors (155298523398).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133113020022 is a wasteful number, since it uses less digits than its factorization.
133113020022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7395167787 (or 7395167784 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 133113020022 its reverse (220020311331), we get a palindrome (353133331353).
The spelling of 133113020022 in words is "one hundred thirty-three billion, one hundred thirteen million, twenty thousand, twenty-two".
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