Base | Representation |
---|---|
bin | 11110010001000011001010… |
… | …111011110111110001100011 |
3 | 122110022111000000021220112220 |
4 | 132101003022323313301203 |
5 | 114421410441432131321 |
6 | 1151035140550522123 |
7 | 40016046000545406 |
oct | 3621031273676143 |
9 | 573274000256486 |
10 | 133113031130211 |
11 | 39460a12907000 |
12 | 12b1a244966343 |
13 | 5937674575a52 |
14 | 24c29c2a65d3d |
15 | 105c8970779c6 |
hex | 7910caef7c63 |
133113031130211 has 16 divisors (see below), whose sum is σ = 195219111024768. Its totient is φ = 80674564318920.
The previous prime is 133113031130171. The next prime is 133113031130213. The reversal of 133113031130211 is 112031130311331.
It is not a de Polignac number, because 133113031130211 - 26 = 133113031130147 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133113031130213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16668294421 + ... + 16668302406.
It is an arithmetic number, because the mean of its divisors is an integer number (12201194439048).
Almost surely, 2133113031130211 is an apocalyptic number.
133113031130211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
133113031130211 is a deficient number, since it is larger than the sum of its proper divisors (62106079894557).
133113031130211 is an equidigital number, since it uses as much as digits as its factorization.
133113031130211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33336596863 (or 33336596841 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 133113031130211 its reverse (112031130311331), we get a palindrome (245144161441542).
The spelling of 133113031130211 in words is "one hundred thirty-three trillion, one hundred thirteen billion, thirty-one million, one hundred thirty thousand, two hundred eleven".
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