Base | Representation |
---|---|
bin | 1100000110110100011110… |
… | …0000011011001000001011 |
3 | 1202010112210121122100000222 |
4 | 3001231013200123020023 |
5 | 3221043022123113423 |
6 | 44151043415220255 |
7 | 2542465335305561 |
oct | 301550740331013 |
9 | 52115717570028 |
10 | 13311303332363 |
11 | 4272323784993 |
12 | 15ab9a067768b |
13 | 75733450816a |
14 | 3403b0437a31 |
15 | 1813ce3513c8 |
hex | c1b4781b20b |
13311303332363 has 2 divisors, whose sum is σ = 13311303332364. Its totient is φ = 13311303332362.
The previous prime is 13311303332311. The next prime is 13311303332381. The reversal of 13311303332363 is 36323330311331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13311303332363 is a prime.
It is not a weakly prime, because it can be changed into another prime (13311303332863) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655651666181 + 6655651666182.
It is an arithmetic number, because the mean of its divisors is an integer number (6655651666182).
Almost surely, 213311303332363 is an apocalyptic number.
13311303332363 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311303332363 is an equidigital number, since it uses as much as digits as its factorization.
13311303332363 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 78732, while the sum is 35.
Adding to 13311303332363 its reverse (36323330311331), we get a palindrome (49634633643694).
The spelling of 13311303332363 in words is "thirteen trillion, three hundred eleven billion, three hundred three million, three hundred thirty-two thousand, three hundred sixty-three".
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