1331131110013 has 4 divisors (see below), whose sum is σ = 1356246791388. Its totient is φ = 1306015428640.

The previous prime is 1331131109993. The next prime is 1331131110053. The reversal of 1331131110013 is 3100111311331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1171940483844 + 159190626169 = 1082562^2 + 398987^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331131110013 - 2⁵ = 1331131109981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331131110053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12557840608 + ... + 12557840713.

It is an arithmetic number, because the mean of its divisors is an integer number (339061697847).

Almost surely, 2^{1331131110013} is an apocalyptic number.

It is an amenable number.

1331131110013 is a deficient number, since it is larger than the sum of its proper divisors (25115681375).

1331131110013 is an equidigital number, since it uses as much as digits as its factorization.

1331131110013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25115681374.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1331131110013 its reverse (3100111311331), we get a palindrome (4431242421344).

The spelling of 1331131110013 in words is "one trillion, three hundred thirty-one billion, one hundred thirty-one million, one hundred ten thousand, thirteen".