133113201420103 has 4 divisors (see below), whose sum is σ = 133113261556800. Its totient is φ = 133113141283408.

The previous prime is 133113201420083. The next prime is 133113201420137. The reversal of 133113201420103 is 301024102311331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133113201420103 - 2⁴¹ = 130914178164551 is a prime.

It is a super-2 number, since 2×133113201420103² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133113201420203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26615950 + ... + 31219147.

It is an arithmetic number, because the mean of its divisors is an integer number (33278315389200).

Almost surely, 2^{133113201420103} is an apocalyptic number.

133113201420103 is a deficient number, since it is larger than the sum of its proper divisors (60136697).

133113201420103 is an equidigital number, since it uses as much as digits as its factorization.

133113201420103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60136696.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 133113201420103 its reverse (301024102311331), we get a palindrome (434137303731434).

The spelling of 133113201420103 in words is "one hundred thirty-three trillion, one hundred thirteen billion, two hundred one million, four hundred twenty thousand, one hundred three".