13311323103121 has 4 divisors (see below), whose sum is σ = 13479820864000. Its totient is φ = 13142825342244.

The previous prime is 13311323103119. The next prime is 13311323103137. The reversal of 13311323103121 is 12130132311331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13311323103121 - 2¹ = 13311323103119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13311323103151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84248880321 + ... + 84248880478.

It is an arithmetic number, because the mean of its divisors is an integer number (3369955216000).

Almost surely, 2^{13311323103121} is an apocalyptic number.

It is an amenable number.

13311323103121 is a deficient number, since it is larger than the sum of its proper divisors (168497760879).

13311323103121 is an equidigital number, since it uses as much as digits as its factorization.

13311323103121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 168497760878.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13311323103121 its reverse (12130132311331), we get a palindrome (25441455414452).

The spelling of 13311323103121 in words is "thirteen trillion, three hundred eleven billion, three hundred twenty-three million, one hundred three thousand, one hundred twenty-one".