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133113240426 = 23132001168071
BaseRepresentation
bin111101111111000101…
…0101101101101101010
3110201120220001020121210
41323332022231231222
54140103442143201
6141052410413550
712421445606025
oct1737612555552
9421526036553
10133113240426
11514a8a54801
122196b4312b6
13c724b8732a
14662ab4c1bc
1536e13251d6
hex1efe2adb6a

133113240426 has 16 divisors (see below), whose sum is σ = 266230081728. Its totient is φ = 44370480000.

The previous prime is 133113240391. The next prime is 133113240427. The reversal of 133113240426 is 624042311331.

It is a super-2 number, since 2×1331132404262 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133113240393 and 133113240402.

It is not an unprimeable number, because it can be changed into a prime (133113240427) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 707971 + ... + 876041.

It is an arithmetic number, because the mean of its divisors is an integer number (16639380108).

Almost surely, 2133113240426 is an apocalyptic number.

133113240426 is an abundant number, since it is smaller than the sum of its proper divisors (133116841302).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133113240426 is a wasteful number, since it uses less digits than its factorization.

133113240426 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 300077.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 133113240426 its reverse (624042311331), we get a palindrome (757155551757).

The spelling of 133113240426 in words is "one hundred thirty-three billion, one hundred thirteen million, two hundred forty thousand, four hundred twenty-six".

Divisors: 1 2 3 6 132001 168071 264002 336142 396003 504213 792006 1008426 22185540071 44371080142 66556620213 133113240426