Base | Representation |
---|---|
bin | 11110010001000011011011… |
… | …000110011000101101010001 |
3 | 122110022111200220120212202021 |
4 | 132101003123012120231101 |
5 | 114421412020343301001 |
6 | 1151035223515251441 |
7 | 40016055502622131 |
oct | 3621033306305521 |
9 | 573274626525667 |
10 | 133113302322001 |
11 | 394610419a4451 |
12 | 12b1a2bb749b81 |
13 | 59376b87c8171 |
14 | 24c2a0aa9aac1 |
15 | 105c8b0c95ba1 |
hex | 7910db198b51 |
133113302322001 has 4 divisors (see below), whose sum is σ = 133113702266352. Its totient is φ = 133112902377652.
The previous prime is 133113302321999. The next prime is 133113302322023. The reversal of 133113302322001 is 100223203311331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 133113302322001 - 21 = 133113302321999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133113302322601) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 199472515 + ... + 200138728.
It is an arithmetic number, because the mean of its divisors is an integer number (33278425566588).
Almost surely, 2133113302322001 is an apocalyptic number.
It is an amenable number.
133113302322001 is a deficient number, since it is larger than the sum of its proper divisors (399944351).
133113302322001 is an equidigital number, since it uses as much as digits as its factorization.
133113302322001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 399944350.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 133113302322001 its reverse (100223203311331), we get a palindrome (233336505633332).
The spelling of 133113302322001 in words is "one hundred thirty-three trillion, one hundred thirteen billion, three hundred two million, three hundred twenty-two thousand, one".
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