Base | Representation |
---|---|
bin | 11110010001000011011011… |
… | …000110011000101101001111 |
3 | 122110022111200220120212202012 |
4 | 132101003123012120231033 |
5 | 114421412020343300444 |
6 | 1151035223515251435 |
7 | 40016055502622126 |
oct | 3621033306305517 |
9 | 573274626525665 |
10 | 133113302321999 |
11 | 394610419a444a |
12 | 12b1a2bb749b7b |
13 | 59376b87c816c |
14 | 24c2a0aa9aabd |
15 | 105c8b0c95b9e |
hex | 7910db198b4f |
133113302321999 has 2 divisors, whose sum is σ = 133113302322000. Its totient is φ = 133113302321998.
The previous prime is 133113302321939. The next prime is 133113302322023. The reversal of 133113302321999 is 999123203311331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133113302321999 - 212 = 133113302317903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133113302321939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556651160999 + 66556651161000.
It is an arithmetic number, because the mean of its divisors is an integer number (66556651161000).
Almost surely, 2133113302321999 is an apocalyptic number.
133113302321999 is a deficient number, since it is larger than the sum of its proper divisors (1).
133113302321999 is an equidigital number, since it uses as much as digits as its factorization.
133113302321999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 708588, while the sum is 50.
The spelling of 133113302321999 in words is "one hundred thirty-three trillion, one hundred thirteen billion, three hundred two million, three hundred twenty-one thousand, nine hundred ninety-nine".
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