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133113333120331 is a prime number
BaseRepresentation
bin11110010001000011011100…
…111011110111110101001011
3122110022111210001112121010011
4132101003130323313311023
5114421412101234322311
61151035230535332351
740016056325454154
oct3621033473676513
9573274701477104
10133113333120331
113946105831a713
1212b1a309b210b7
1359376c1cbc625
1424c2a10bd692b
15105c8b382b321
hex7910dcef7d4b

133113333120331 has 2 divisors, whose sum is σ = 133113333120332. Its totient is φ = 133113333120330.

The previous prime is 133113333120293. The next prime is 133113333120353. The reversal of 133113333120331 is 133021333311331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133113333120331 - 27 = 133113333120203 is a prime.

It is a super-2 number, since 2×1331133331203312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133113333120293 and 133113333120302.

It is not a weakly prime, because it can be changed into another prime (133113333120631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556666560165 + 66556666560166.

It is an arithmetic number, because the mean of its divisors is an integer number (66556666560166).

Almost surely, 2133113333120331 is an apocalyptic number.

133113333120331 is a deficient number, since it is larger than the sum of its proper divisors (1).

133113333120331 is an equidigital number, since it uses as much as digits as its factorization.

133113333120331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13122, while the sum is 31.

Adding to 133113333120331 its reverse (133021333311331), we get a palindrome (266134666431662).

The spelling of 133113333120331 in words is "one hundred thirty-three trillion, one hundred thirteen billion, three hundred thirty-three million, one hundred twenty thousand, three hundred thirty-one".