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13311400457 is a prime number
BaseRepresentation
bin11000110010110101…
…11101101000001001
31021100200202012120202
430121122331220021
5204230204303312
610040513301545
7650604015455
oct143132755011
937320665522
1013311400457
115710a36203
1226b5b648b5
131341a61924
14903c69665
1552d9639c2
hex3196bda09

13311400457 has 2 divisors, whose sum is σ = 13311400458. Its totient is φ = 13311400456.

The previous prime is 13311400441. The next prime is 13311400471. The reversal of 13311400457 is 75400411331.

13311400457 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13190752201 + 120648256 = 114851^2 + 10984^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311400457 - 24 = 13311400441 is a prime.

It is not a weakly prime, because it can be changed into another prime (13311400657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655700228 + 6655700229.

It is an arithmetic number, because the mean of its divisors is an integer number (6655700229).

Almost surely, 213311400457 is an apocalyptic number.

It is an amenable number.

13311400457 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311400457 is an equidigital number, since it uses as much as digits as its factorization.

13311400457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 13311400457 its reverse (75400411331), we get a palindrome (88711811788).

The spelling of 13311400457 in words is "thirteen billion, three hundred eleven million, four hundred thousand, four hundred fifty-seven".