Base | Representation |
---|---|
bin | 11110010001000100000110… |
… | …001101101101000010110001 |
3 | 122110022120120022200021202111 |
4 | 132101010012031231002301 |
5 | 114421420011032114333 |
6 | 1151035423355045321 |
7 | 40016112435116035 |
oct | 3621040615550261 |
9 | 573276508607674 |
10 | 133114025660593 |
11 | 3946138323443a |
12 | 12b1a481a40841 |
13 | 59377a2619473 |
14 | 24c2a78b8c1c5 |
15 | 105c9045284cd |
hex | 79110636d0b1 |
133114025660593 has 2 divisors, whose sum is σ = 133114025660594. Its totient is φ = 133114025660592.
The previous prime is 133114025660579. The next prime is 133114025660701. The reversal of 133114025660593 is 395066520411331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 81407816026384 + 51706209634209 = 9022628^2 + 7190703^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133114025660593 is a prime.
It is a super-2 number, since 2×1331140256605932 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133114025660543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66557012830296 + 66557012830297.
It is an arithmetic number, because the mean of its divisors is an integer number (66557012830297).
Almost surely, 2133114025660593 is an apocalyptic number.
It is an amenable number.
133114025660593 is a deficient number, since it is larger than the sum of its proper divisors (1).
133114025660593 is an equidigital number, since it uses as much as digits as its factorization.
133114025660593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1749600, while the sum is 49.
The spelling of 133114025660593 in words is "one hundred thirty-three trillion, one hundred fourteen billion, twenty-five million, six hundred sixty thousand, five hundred ninety-three".
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