Base | Representation |
---|---|
bin | 11110010001000100000110… |
… | …001101101101000011010111 |
3 | 122110022120120022200021210220 |
4 | 132101010012031231003113 |
5 | 114421420011032120011 |
6 | 1151035423355045423 |
7 | 40016112435116121 |
oct | 3621040615550327 |
9 | 573276508607726 |
10 | 133114025660631 |
11 | 39461383234474 |
12 | 12b1a481a40873 |
13 | 59377a26194a2 |
14 | 24c2a78b8c211 |
15 | 105c904528506 |
hex | 79110636d0d7 |
133114025660631 has 4 divisors (see below), whose sum is σ = 177485367547512. Its totient is φ = 88742683773752.
The previous prime is 133114025660593. The next prime is 133114025660701. The reversal of 133114025660631 is 136066520411331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133114025660631 is a prime.
It is a super-2 number, since 2×1331140256606312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133114025160631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22185670943436 + ... + 22185670943441.
It is an arithmetic number, because the mean of its divisors is an integer number (44371341886878).
Almost surely, 2133114025660631 is an apocalyptic number.
133114025660631 is a deficient number, since it is larger than the sum of its proper divisors (44371341886881).
133114025660631 is an equidigital number, since it uses as much as digits as its factorization.
133114025660631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44371341886880.
The product of its (nonzero) digits is 233280, while the sum is 42.
The spelling of 133114025660631 in words is "one hundred thirty-three trillion, one hundred fourteen billion, twenty-five million, six hundred sixty thousand, six hundred thirty-one".
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