13311420000000 has 576 divisors, whose sum is σ = 45022976928384. Its totient is φ = 3490560000000.

The previous prime is 13311419999993. The next prime is 13311420000007. The reversal of 13311420000000 is 2411331.

It is an interprime number because it is at equal distance from previous prime (13311419999993) and next prime (13311420000007).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311420000007) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3659998182 + ... + 3660001818.

Almost surely, 2^{13311420000000} is an apocalyptic number.

13311420000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311420000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22511488464192).

13311420000000 is an abundant number, since it is smaller than the sum of its proper divisors (31711556928384).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311420000000 is an frugal number, since it uses more digits than its factorization.

13311420000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3752 (or 3708 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 13311420000000 its reverse (2411331), we get a palindrome (13311422411331).

The spelling of 13311420000000 in words is "thirteen trillion, three hundred eleven billion, four hundred twenty million", and thus it is an aban number.