Base | Representation |
---|---|
bin | 11000110010110110… |
… | …00010011110101100 |
3 | 1021100200210012211212 |
4 | 30121123002132230 |
5 | 204230210422312 |
6 | 10040513533552 |
7 | 650604130430 |
oct | 143133023654 |
9 | 37320705755 |
10 | 13311420332 |
11 | 5710a4a131 |
12 | 26b5b742b8 |
13 | 1341a6a9a2 |
14 | 903c729c0 |
15 | 52d969822 |
hex | 3196c27ac |
13311420332 has 24 divisors (see below), whose sum is σ = 26642196000. Its totient is φ = 5700746880.
The previous prime is 13311420319. The next prime is 13311420337. The reversal of 13311420332 is 23302411331.
13311420332 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×133114203322 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13311420298 and 13311420307.
It is not an unprimeable number, because it can be changed into a prime (13311420337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 133457 + ... + 210792.
It is an arithmetic number, because the mean of its divisors is an integer number (1110091500).
Almost surely, 213311420332 is an apocalyptic number.
It is an amenable number.
13311420332 is an abundant number, since it is smaller than the sum of its proper divisors (13330775668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13311420332 is a wasteful number, since it uses less digits than its factorization.
13311420332 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 345641 (or 345639 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13311420332 its reverse (23302411331), we get a palindrome (36613831663).
Subtracting 13311420332 from its reverse (23302411331), we obtain a palindrome (9990990999).
The spelling of 13311420332 in words is "thirteen billion, three hundred eleven million, four hundred twenty thousand, three hundred thirty-two".
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