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13311454240 = 25571723113269
BaseRepresentation
bin11000110010110110…
…01010110000100000
31021100200211221100201
430121123022300200
5204230213013430
610040514354544
7650604331330
oct143133126040
937320757321
1013311454240
115710a72657
1226b5b8ba54
131341a80256
14903c810c0
1552d9748ca
hex3196cac20

13311454240 has 384 divisors, whose sum is σ = 40210007040. Its totient is φ = 4057202688.

The previous prime is 13311454213. The next prime is 13311454243. The reversal of 13311454240 is 4245411331.

It is a super-2 number, since 2×133114542402 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (28).

It is a junction number, because it is equal to n+sod(n) for n = 13311454199 and 13311454208.

It is not an unprimeable number, because it can be changed into a prime (13311454243) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 49484826 + ... + 49485094.

It is an arithmetic number, because the mean of its divisors is an integer number (104713560).

Almost surely, 213311454240 is an apocalyptic number.

13311454240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311454240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20105003520).

13311454240 is an abundant number, since it is smaller than the sum of its proper divisors (26898552800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311454240 is a wasteful number, since it uses less digits than its factorization.

13311454240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 444 (or 436 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 13311454240 its reverse (4245411331), we get a palindrome (17556865571).

The spelling of 13311454240 in words is "thirteen billion, three hundred eleven million, four hundred fifty-four thousand, two hundred forty".