Base | Representation |
---|---|
bin | 11000110010111000… |
… | …00110100011101011 |
3 | 1021100201022101100112 |
4 | 30121130012203223 |
5 | 204230243333204 |
6 | 10040523524535 |
7 | 650606401412 |
oct | 143134064353 |
9 | 37321271315 |
10 | 13311699179 |
11 | 571111a689 |
12 | 26b608974b |
13 | 1341b3789c |
14 | 903d06479 |
15 | 52d9c226e |
hex | 3197068eb |
13311699179 has 2 divisors, whose sum is σ = 13311699180. Its totient is φ = 13311699178.
The previous prime is 13311699151. The next prime is 13311699199. The reversal of 13311699179 is 97199611331.
13311699179 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (97199611331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13311699179 - 28 = 13311698923 is a prime.
It is not a weakly prime, because it can be changed into another prime (13311699199) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655849589 + 6655849590.
It is an arithmetic number, because the mean of its divisors is an integer number (6655849590).
Almost surely, 213311699179 is an apocalyptic number.
13311699179 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311699179 is an equidigital number, since it uses as much as digits as its factorization.
13311699179 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 275562, while the sum is 50.
The spelling of 13311699179 in words is "thirteen billion, three hundred eleven million, six hundred ninety-nine thousand, one hundred seventy-nine".
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