1331200143121 has 2 divisors, whose sum is σ = 1331200143122. Its totient is φ = 1331200143120.

The previous prime is 1331200143101. The next prime is 1331200143167. The reversal of 1331200143121 is 1213410021331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 770596042896 + 560604100225 = 877836^2 + 748735^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331200143121 - 2³³ = 1322610208529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1331200143092 and 1331200143101.

It is not a weakly prime, because it can be changed into another prime (1331200143101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665600071560 + 665600071561.

It is an arithmetic number, because the mean of its divisors is an integer number (665600071561).

Almost surely, 2^{1331200143121} is an apocalyptic number.

It is an amenable number.

1331200143121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331200143121 is an equidigital number, since it uses as much as digits as its factorization.

1331200143121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1331200143121 its reverse (1213410021331), we get a palindrome (2544610164452).

The spelling of 1331200143121 in words is "one trillion, three hundred thirty-one billion, two hundred million, one hundred forty-three thousand, one hundred twenty-one".