133120041555131 has 2 divisors, whose sum is σ = 133120041555132. Its totient is φ = 133120041555130.

The previous prime is 133120041555029. The next prime is 133120041555203. The reversal of 133120041555131 is 131555140021331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133120041555131 - 2³⁴ = 133102861685947 is a prime.

It is a super-2 number, since 2×133120041555131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133120041555091 and 133120041555100.

It is not a weakly prime, because it can be changed into another prime (133120041551131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66560020777565 + 66560020777566.

It is an arithmetic number, because the mean of its divisors is an integer number (66560020777566).

Almost surely, 2^{133120041555131} is an apocalyptic number.

133120041555131 is a deficient number, since it is larger than the sum of its proper divisors (1).

133120041555131 is an equidigital number, since it uses as much as digits as its factorization.

133120041555131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 35.

Adding to 133120041555131 its reverse (131555140021331), we get a palindrome (264675181576462).

The spelling of 133120041555131 in words is "one hundred thirty-three trillion, one hundred twenty billion, forty-one million, five hundred fifty-five thousand, one hundred thirty-one".