133121320333 has 4 divisors (see below), whose sum is σ = 133865015040. Its totient is φ = 132377625628.

The previous prime is 133121320313. The next prime is 133121320357. The reversal of 133121320333 is 333023121331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133121320333 - 2¹³ = 133121312141 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133121320298 and 133121320307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133121320313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 371847085 + ... + 371847442.

It is an arithmetic number, because the mean of its divisors is an integer number (33466253760).

Almost surely, 2^133121320333 is an apocalyptic number.

It is an amenable number.

133121320333 is a deficient number, since it is larger than the sum of its proper divisors (743694707).

133121320333 is an equidigital number, since it uses as much as digits as its factorization.

133121320333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 743694706.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 133121320333 its reverse (333023121331), we get a palindrome (466144441664).

The spelling of 133121320333 in words is "one hundred thirty-three billion, one hundred twenty-one million, three hundred twenty thousand, three hundred thirty-three".