Base | Representation |
---|---|
bin | 1100000110110111100101… |
… | …1011111011010000010011 |
3 | 1202010121221222212222021002 |
4 | 3001231321123323100103 |
5 | 3221101231044422120 |
6 | 44151302501452215 |
7 | 2542525156423313 |
oct | 301557133732023 |
9 | 52117858788232 |
10 | 13312141014035 |
11 | 4272713612596 |
12 | 15abb9511106b |
13 | 757438c225a6 |
14 | 34044d7b1443 |
15 | 18142cb6d375 |
hex | c1b796fb413 |
13312141014035 has 32 divisors (see below), whose sum is σ = 16517561860800. Its totient is φ = 10292953079808.
The previous prime is 13312141013993. The next prime is 13312141014037. The reversal of 13312141014035 is 53041014121331.
It is not a de Polignac number, because 13312141014035 - 26 = 13312141013971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13312141013989 and 13312141014007.
It is not an unprimeable number, because it can be changed into a prime (13312141014037) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 121926329 + ... + 122035461.
It is an arithmetic number, because the mean of its divisors is an integer number (516173808150).
Almost surely, 213312141014035 is an apocalyptic number.
13312141014035 is a deficient number, since it is larger than the sum of its proper divisors (3205420846765).
13312141014035 is a wasteful number, since it uses less digits than its factorization.
13312141014035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115127.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 13312141014035 its reverse (53041014121331), we get a palindrome (66353155135366).
The spelling of 13312141014035 in words is "thirteen trillion, three hundred twelve billion, one hundred forty-one million, fourteen thousand, thirty-five".
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