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1331214113 is a prime number
BaseRepresentation
bin100111101011000…
…1011011100100001
310102202220200110102
41033112023130201
510211242322423
6340032312145
744663063465
oct11726133441
93382820412
101331214113
11623487959
123119a2655
13182a46778
14c8b284a5
157bd08c28
hex4f58b721

1331214113 has 2 divisors, whose sum is σ = 1331214114. Its totient is φ = 1331214112.

The previous prime is 1331214107. The next prime is 1331214139. The reversal of 1331214113 is 3114121331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 824378944 + 506835169 = 28712^2 + 22513^2 .

It is an emirp because it is prime and its reverse (3114121331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1331214113 - 24 = 1331214097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1331214103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665607056 + 665607057.

It is an arithmetic number, because the mean of its divisors is an integer number (665607057).

Almost surely, 21331214113 is an apocalyptic number.

It is an amenable number.

1331214113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331214113 is an equidigital number, since it uses as much as digits as its factorization.

1331214113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 216, while the sum is 20.

The square root of 1331214113 is about 36485.8070076571. The cubic root of 1331214113 is about 1100.0589811349.

Adding to 1331214113 its reverse (3114121331), we get a palindrome (4445335444).

The spelling of 1331214113 in words is "one billion, three hundred thirty-one million, two hundred fourteen thousand, one hundred thirteen".