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1331221103132 = 22586756724949
BaseRepresentation
bin10011010111110010111…
…101100000001000011100
311201021010002100211012012
4103113302331200020130
5133302320100300012
62455315440130352
7165114620450564
oct23276275401034
94637102324165
101331221103132
11473627676068
12195bbb3069b8
13986c246226b
1448607c57da4
1524964d57622
hex135f2f6021c

1331221103132 has 12 divisors (see below), whose sum is σ = 2330034046200. Its totient is φ = 665497089936.

The previous prime is 1331221103123. The next prime is 1331221103141. The reversal of 1331221103132 is 2313011221331.

It is an interprime number because it is at equal distance from previous prime (1331221103123) and next prime (1331221103141).

It is a junction number, because it is equal to n+sod(n) for n = 1331221103098 and 1331221103107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28339007 + ... + 28385942.

It is an arithmetic number, because the mean of its divisors is an integer number (194169503850).

Almost surely, 21331221103132 is an apocalyptic number.

It is an amenable number.

1331221103132 is a deficient number, since it is larger than the sum of its proper divisors (998812943068).

1331221103132 is a wasteful number, since it uses less digits than its factorization.

1331221103132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56730820 (or 56730818 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1331221103132 its reverse (2313011221331), we get a palindrome (3644232324463).

The spelling of 1331221103132 in words is "one trillion, three hundred thirty-one billion, two hundred twenty-one million, one hundred three thousand, one hundred thirty-two".

Divisors: 1 2 4 5867 11734 23468 56724949 113449898 226899796 332805275783 665610551566 1331221103132