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13312221131953 is a prime number
BaseRepresentation
bin1100000110110111111000…
…1101100011010010110001
31202010122011120122101101101
43001231332031203102301
53221101412102210303
644151314443004401
72542530151420252
oct301557615432261
952118146571341
1013312221131953
114272754864347
1215abbb7b09701
1375744c6c4543
1434045a2a8b29
15181434be6d1d
hexc1b7e3634b1

13312221131953 has 2 divisors, whose sum is σ = 13312221131954. Its totient is φ = 13312221131952.

The previous prime is 13312221131939. The next prime is 13312221132011. The reversal of 13312221131953 is 35913112221331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12686084433009 + 626136698944 = 3561753^2 + 791288^2 .

It is a cyclic number.

It is not a de Polignac number, because 13312221131953 - 233 = 13303631197361 is a prime.

It is not a weakly prime, because it can be changed into another prime (13312221131903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656110565976 + 6656110565977.

It is an arithmetic number, because the mean of its divisors is an integer number (6656110565977).

Almost surely, 213312221131953 is an apocalyptic number.

It is an amenable number.

13312221131953 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312221131953 is an equidigital number, since it uses as much as digits as its factorization.

13312221131953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 29160, while the sum is 37.

The spelling of 13312221131953 in words is "thirteen trillion, three hundred twelve billion, two hundred twenty-one million, one hundred thirty-one thousand, nine hundred fifty-three".