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1331230118400 = 29335272136047
BaseRepresentation
bin10011010111110011011…
…111111001001000000000
311201021010201022211211000
4103113303133321020000
5133302324402242100
62455320401252000
7165115060206300
oct23276337711000
94637121284730
101331230118400
114736317733a6
12196002334000
13986c429a840
1448609123600
1524965a38900
hex135f37f9200

1331230118400 has 1440 divisors, whose sum is σ = 6122263150080. Its totient is φ = 280828477440.

The previous prime is 1331230118399. The next prime is 1331230118419. The reversal of 1331230118400 is 48110321331.

1331230118400 is a `hidden beast` number, since 1 + 3 + 312 + 301 + 1 + 8 + 40 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (1440).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 220144177 + ... + 220150223.

It is an arithmetic number, because the mean of its divisors is an integer number (4251571632).

Almost surely, 21331230118400 is an apocalyptic number.

1331230118400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1331230118400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3061131575040).

1331230118400 is an abundant number, since it is smaller than the sum of its proper divisors (4791033031680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1331230118400 is a wasteful number, since it uses less digits than its factorization.

1331230118400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6111 (or 6077 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 1331230118400 its reverse (48110321331), we get a palindrome (1379340439731).

The spelling of 1331230118400 in words is "one trillion, three hundred thirty-one billion, two hundred thirty million, one hundred eighteen thousand, four hundred".