Base | Representation |
---|---|
bin | 1100000110111000001100… |
… | …0010111000011111111111 |
3 | 1202010122101020020011001221 |
4 | 3001232003002320133333 |
5 | 3221102043332040221 |
6 | 44151330501014211 |
7 | 2542532154601342 |
oct | 301560302703777 |
9 | 52118336204057 |
10 | 13312302221311 |
11 | 4272796609a45 |
12 | 15b001b0b4367 |
13 | 757463446702 |
14 | 340466d76459 |
15 | 18143bdb3541 |
hex | c1b830b87ff |
13312302221311 has 4 divisors (see below), whose sum is σ = 13312313091000. Its totient is φ = 13312291351624.
The previous prime is 13312302221297. The next prime is 13312302221341. The reversal of 13312302221311 is 11312220321331.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 13312302221311 - 25 = 13312302221279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13312302221341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3324661 + ... + 6138238.
It is an arithmetic number, because the mean of its divisors is an integer number (3328078272750).
Almost surely, 213312302221311 is an apocalyptic number.
13312302221311 is a deficient number, since it is larger than the sum of its proper divisors (10869689).
13312302221311 is an equidigital number, since it uses as much as digits as its factorization.
13312302221311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10869688.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13312302221311 its reverse (11312220321331), we get a palindrome (24624522542642).
The spelling of 13312302221311 in words is "thirteen trillion, three hundred twelve billion, three hundred two million, two hundred twenty-one thousand, three hundred eleven".
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