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13312405061257 is a prime number
BaseRepresentation
bin1100000110111000100100…
…1011001011111010001001
31202010122122101201221221211
43001232021023023322021
53221102301143430012
644151345013133121
72542534543662301
oct301561113137211
952118571657854
1013312405061257
114272839670135
1215b004962a1a1
1375747b842a53
143404768a6601
15181445e296a7
hexc1b892cbe89

13312405061257 has 2 divisors, whose sum is σ = 13312405061258. Its totient is φ = 13312405061256.

The previous prime is 13312405061149. The next prime is 13312405061269. The reversal of 13312405061257 is 75216050421331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11277970676361 + 2034434384896 = 3358269^2 + 1426336^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13312405061257 is a prime.

It is not a weakly prime, because it can be changed into another prime (13312405061057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656202530628 + 6656202530629.

It is an arithmetic number, because the mean of its divisors is an integer number (6656202530629).

Almost surely, 213312405061257 is an apocalyptic number.

It is an amenable number.

13312405061257 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312405061257 is an equidigital number, since it uses as much as digits as its factorization.

13312405061257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 40.

Adding to 13312405061257 its reverse (75216050421331), we get a palindrome (88528455482588).

The spelling of 13312405061257 in words is "thirteen trillion, three hundred twelve billion, four hundred five million, sixty-one thousand, two hundred fifty-seven".