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13312414080000 = 210325472101467
BaseRepresentation
bin1100000110111000100110…
…1101100101110000000000
31202010122200000201011100100
43001232021231211300000
53221102311001030000
644151345534322400
72542535013434100
oct301561155456000
952118600634310
1013312414080000
114272843770042
1215b0050659400
1375748067ca99
14340477b73200
15181446b0ba00
hexc1b89b65c00

13312414080000 has 1980 divisors, whose sum is σ = 56550065117832. Its totient is φ = 3006259200000.

The previous prime is 13312414079963. The next prime is 13312414080011. The reversal of 13312414080000 is 8041421331.

13312414080000 is a `hidden beast` number, since 13 + 3 + 1 + 241 + 408 + 0 + 0 + 0 + 0 = 666.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 179 ways as a sum of consecutive naturals, for example, 28506239767 + ... + 28506240233.

Almost surely, 213312414080000 is an apocalyptic number.

13312414080000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13312414080000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (28275032558916).

13312414080000 is an abundant number, since it is smaller than the sum of its proper divisors (43237651037832).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13312414080000 is a wasteful number, since it uses less digits than its factorization.

13312414080000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 628 (or 585 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

The spelling of 13312414080000 in words is "thirteen trillion, three hundred twelve billion, four hundred fourteen million, eighty thousand".